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-16x^2+16x+2=0
a = -16; b = 16; c = +2;
Δ = b2-4ac
Δ = 162-4·(-16)·2
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8\sqrt{6}}{2*-16}=\frac{-16-8\sqrt{6}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8\sqrt{6}}{2*-16}=\frac{-16+8\sqrt{6}}{-32} $
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